If y = 5x2 – 3x + k does not hit the x-axis, then what is/are the value(s) of k?

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  k > 9/20

Step-by-step explanation:

If the parabola does not touch the x-axis, the discriminant is negative. That means ...

  b^2 -4ac < 0

  (-3)^2 -4(5)(k) < 0

  9 < 20k . . . . . . . . . add 20k

  k > 9/20 . . . . . . . . .divide by 20

Discriminant  |  D < 0 (Because doesn't intercept any x-values)

Therefore, the value of k must be greater than 9/20

so k > 9/20

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

answer: b

step-by-step explanation: