The indicated function y1(x)
is a solution of the given differential equation. Use reduction of order or formula (5) in Section 4.2,
y2 = y1(x)
e−∫P(x) dx
y
2
1
(x)

dx
(5)
as instructed, to find a second solution
y2(x).
x2y'' + 2xy' − 6y = 0; y1 = x2
y2 =

step-by-stp

the correct answer is the section c

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet