in which of the tables below are x and y inversely proportional find the constant of variation (x, 1, 5, 3, 2) (y, 15, 3, 5, 7.2) If x and y are inversely proportional enter the constant of variation

hello there!

i believe the answer is

(cot2+1)/sec2=cot2

    csc2/sec2=cot2

  (1/sin2)/(1/cos2)=cot2

  (1/sin2)(cos2/1)=cot2

  cos2/sin2=cot2

  (1/tan2)=cot2

  (cot2)=(cot2)

hope this !

hyperz ^_^

it will take 9 minutes                

6+6=12 so that just tells you what it is one half is 6 the next one is 6