Which group of ordered pairs are on the line given by the equation 5x−2y=6?

(0, -3), (2, 2), (4,7) these are just some points

Step-by-step explanation:

Put the equation in y=mx+b format. It will be 2y=5x-6.

y=5/2x -3

the first point will be (0, -3) because of the y-intercept which is negative 3. You can graph the slope from that point to get (2, 2) and (4, 7). You can get more points too

There are infinite ordered pairs are on the line because it has infinite solutions.

Step-by-step explanation:

5x - 2y = 6

-5x        -5x

-2y = -5x + 6

-2y/2 = -5x/-2 + 6/-2

y = 5/2x - 3

5x - 2(5/2x - 3) = 6

5x - 5x + 6 = 6

6 = 6

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3