I need to graph the points where the line crosses the axes. Also a basic explanation of how to do so would be helpful

(0,6) and (-2, 0)

Step-by-step explanation:

All straight lines follow the equation, y = mx + c. where c is the y-intercept (the point where the line meets the y-axis) and m is the gradient.

In this equation, c = 6. So, the point where the line meets the y-axis is (0, 6).

Remember: the point where the line meets the y-axis always has an x-coordinate of 0 and the point where the line meets the x-axis has a y-coordinate of 0.

using this information, we can substitute y in the equation with 0 becoming

0 = 6 + 3x

now we can solve for x.

0 -6 = 3x

-6 / 3 = x

x = -2

the coordinate is (-2, 0)

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3