What values are excluded from the domain and range of the function f(x)=x+3/2x+5

here u go bro

Step-by-step explanation:

With functions domains, I think it is helpful to consider what you CANNOT use (undefined or answers that are not real). For most functions (there are specific exceptions, see below) there are two main concerns:

1. you cannot have negative under a square root (or any "even radical")

2. you cannot have zero in the denominator

1.so for each function: ask yourself "Is there a square root (or other even radical)?" if yes, determine the values of x that make the inside of the radical negative. These value must be excluded from domain

   ex.: f(x)=√(x+1) , if x is less than -1 the part under radical is negative, so we can only use value greater than or equal to -1

Next, ask yourself "are there any fractions?" if yes, determine what values of x will give you a zero in the denominator. Since you can't have zero in the denominator (undefined) those value must be excluded from the domain.

ex.: f(x)=(x+3)/(x-5) , so the denominator is (x-5) so (x-5)≠0  therefore x≠5. 5 must be excluded form the domain.

if you don't have either of these "problems" your domain is All Real Numbers* (nothing is excluded)

* there are exceptions such as logarithms and some trig functions

***It is also helpful to note that polynomials always have a domain of: All Real Numbers***

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

-3.5 degrees per hour

step-by-step explanation:

find the unit rate:

-12   1/4 degrees           12.25 degrees

= - = -3.5 degrees per hour

      3   1/2 hours               3.5 hours