A triangle with a base of 4 centimeters and height of 3.5 centimeters. She found the area of the enlarged triangle. Her work is shown below. One-half (4) (3.5) (5) = 35 centimeters squared What was Beth's error? She should have divided One-half (4) (3.5) by 5. She should have divided One-half (4) (3.5) by 5 squared. She should have multiplied (4) (3.5) by 5. She should have multiplied One-half (4) (3.5) by 5 squared.

She should have multiplied One-half (4) (3.5) by 5 squared.

Step-by-step explanation:

The calculation of Beth is wrong. Since Beth enlarged the triangle below by a scale of 5, she should find the area of the traingle and then multiply by 5².

This will be:

= 1/2 × 4 × 3.5 × 5²

= 2 × 3.5 × 25

= 175cm²

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

answer: i'm not sure

step-by-step explanation: