Identify an equation in point-slope form for the line parallel to y = -2/3 x+8 that
passes through (4,-5).
O A. y-4=2/3(x+5)
OB. 7-5=-2/3(x+4)
O C. y+5 = 3/2(x-4)
O D. y +5 = -2/3 (x-4)

the answer is 40.

proof:

2: 10

step-by-step explanation:

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.

the answer to this is 4340

hope this if needed hmu