A boat travels with velocity vector (25, 25 StartRoot 3 EndRoot). What is the directional bearing of the boat? N 30° E E 30° S E 30° N N 30° W

The directional bearing of the boat is N 30º E

Step-by-step explanation:

Let , where is the vector velocity. Given that such vector is represented in rectangular, a positive value in the first component is the value of the vector in the east direction, whereas a positive value in the second component is in the north direction. The directional bearing of the boat (), measured in sexagesimal degrees, is determined by trigonometrical means:

(1)

If we know that and , then the directional bearing of the boat is:

In consequence, we conclude that the direction bearing of the boat is 30 degrees to the East from the North (N 30º E).

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

believe it or not anna is correct good job anna give me a fist bump there u go gal