Write a linear function $f$ with the values $f(0)=8$ and $\ f(4)=20$ .

f(x) = 3x + 8 is the required linear function.

Step-by-step explanation:

We know that the slope-intercept form of linear equation is

y  = mx+b

here

Given initial value

f(0) = 8

Thus, the y-intercept = b = 8

Also given

at x = 4, f(4) = 20

so

substituting the point (4, 20) and y-intercept b=8 in the slope-intercept form to determine the slope

y = mx+b                        

20 = m(4) + 8

20 = 4m + 8

4m = 20-8

4m = 12

Dividing both sides by 4

m = 3

Thus, the slope = m = 3

Now, substituting m = 3 and b = 8 in the slope-intercept of linear function

y = mx+b

y = 3x + 8

or

f(x) = 3x + 8

Thus,

f(x) = 3x + 8 is the required linear function.

VERIFICATION:

Given the linear function

f(x) = 3x + 8

plug in x = 0

f(0) = 3(0) + 8

f(0) = 8

plug in x = 4

f(x) = 3x + 8

f(4) = 3(4) + 8

f(4) = 12+8

f(4) = 20

h who knows

step-by-step explanation:

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d