I NEED HELP ASAP PL 20 POINTS AND A chemistry teacher needs to make a 42% sulphuric acid solution. The acid solutions available are 4 liters of 30% sulphuric acid and 50% sulphuric acid, by volume. How many liters of the 50% sulphuric acid solution must be mixed with the 4 liters in order to make the 42% sulphuric acid solution?

4 liters of 30%  and 6 liters of 50% acid.

Step-by-step explanation:

Let the volume of 30% acid be x,  then the volume of 50% acid will be

(10 - x) liters.

So we have the equation:

0.30x  + 0.50(10 - x) = 0.42* 10

0.30x +  5 - 0.50x = 4.2

0.80 = 0.20x

x = 4  liters.

So we need 4 liters of 30% acid and 6 liters of 50% acid.

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step-by-step explanation:

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