Write a linear equation that is parallel to 5x+2y=-8 and passes through the point (8,-9)

y= -5/2x+11

Step-by-step explanation:

You want to first reorder the equation into slope intercept form

First subtract 5x from both sides

5x-5x+2y = -8-5x

It should look like:

2y = -5x - 8

Then isolate your y variable

Since the y is multiplied with 2 divide by 2 to isolate and remember to divide the other side as well

It should look like:

2y/2 = -5/2x -8/2

This will result in y = -5/2x - 4

Now since the line is parallel the slope will be the same but to pass through a different point the y intercept will have to change.

Re make your equation and you have:

y = -5/2x + b

Now plug in your (x,y) value for the x and y in the slope intercept form.

-9 = -5/2(8) +b

Now solve for b:

-9 = -40/2 +b

-9 = -20 +b

Isolate your y intercept by adding 20 to both sides

-9 + 20 = -20 + 20 +b

which results with b = 11

Now you have all components to your final slope intercept form giving you the answer

y = -5/2x + 11

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step-by-step explanation: