Answers: 1
Mathematics, 22.06.2019 01:00
For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)
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Mathematics, 22.06.2019 03:20
The height of a box can be found by dividing its volume by the area of its base,bottom.what is the height of a box that has a volume of 26.35 cubic centimeter and a base area of 4 1/4 square centimeter?
Answers: 1
Mathematics, 22.06.2019 04:30
Draw a geometric diagram of this scenario using two parallel lines and one transversal. (remember that a transversal is a line which cuts across parallel lines.) label the angles, parallel lines, and transversal as indicated in the diagram above.
Answers: 2
Expand the function f(x)=(x+7)³...
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