Z^2-9z+14=0 solve with steps ?

=

−

±

2

−

4

√

2

z=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c{2{\color{#c92786}{a}}}

z=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

2

−

9

+

1

4

=

0

z^{2}-9z+14=0

z2−9z+14=0

=

1

a={\color{#c92786}{1}}

a=1

=

−

9

b={\color{#e8710a}{-9}}

b=−9

=

1

4

c={\color{#129eaf}{14}}

c=14

=

−

(

−

9

)

±

(

−

9

)

2

−

4

⋅

1

⋅

1

4

√

2

⋅

1 is for the quadratic formula

next you simplify so

Evaluate the exponent

Multiply the numbers

Subtract the numbers

Evaluate the square root

Multiply the numbers

=

9

±

5

2

then separate the equations so

To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.

=

9

+

5

2

z=\frac{9+5}{2}

z=29+5​

=

9

−

5

2

then solve

=

7

z=7

z=7

=

2

so the solution is

z=7

z=2

Step-by-step explanation:

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.