Please help, I'll give Brainliest! An old bone contains 80% of its original carbon-14. Use the half-life model to find the age of the bone. Find an equation equivalent to P(t) = A()^(). I already solved this, it's C. .

Find the value of for this problem

1843 years

Step-by-step explanation:

Let the number of atoms originally present be A

Let the number of atoms at time t be P(t)

P(t) = 0.8 A

Hence;

P(t)/A= 0.8A/A  = 0.8

Thus the value of P(t)/A= 0.8

Since half life of C-14 = 5730 years

Age of the bone can be obtained from;

0.693/5730 = 2.303/t log (A/0.8A)

1.21 * 10^-4 = 2.303/t log(1/0.8)

1.21 * 10^-4 = 0.223/t

t = 0.223/1.21 * 10^-4

So;

t = 1843 years

three-fourths of an hour

36÷48=0.75

0.75=

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step-by-step explanation:

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