A three digit number is selected at random from the set of all three digit numbers. The probability that the selected number has all the three digits the same is:.A.1/9B. 1/10C. 1/50D. 1/100

1 /100

Step-by-step explanation:

Probability = (number of required outcomes / number of total possible outcomes)

Total possible outcomes = count of all 3 digit numbers ={100, 101,... 999} = 900

Required outcome = count of Three digit numbers with all 3 digits being the same = {111,222,333,444,555,666,777,888,999} = 9

Hence, probability that selected number has all 3 digits being the same :

9 / 900 = 1 /100

is there any photos or whatever?