Give three points that lie on a line with a
slope of -2/5

The three points that lie on a line y = -2/5x with a slope -2/5 will be:

Please check the attached graph also.

Step-by-step explanation:

We know that the slope-intercept form of the line equation is

where m is the slope and b is the y-intercept

Given

slope = m = -2/5

We suppose the line passes through the origin.

so b = 0

substituting m = -2/5 and b = 0 in the slope-intercept form

y = -2/5x + 0

y = -2/5x

Thus, the equation of line with the slope m = -2/5 and passes through the origin (0, 0) will be:

y = -2/5x

As the equation of line passes through (0, 0), thus the point (0, 0) lies on the line.

Putting x = 0 in the equation y = -2/5x

y = -2/5 × (0)

y = 0

Thus, (0, 0) is the point which also passes through the line

Putting x = 5 in the equation y = -2/5x

y = -2/5 × 5

y = -2

Thus, (5, -2) is the point which also passes through the line

Now, putting x = 10 in the equation y = -2/5x

y = -2/5 × 10

y = -4

Thus, (10, -4) is the point which also passes through the line.

Thus, the three points that lie on a line y = -2/5x with a slope -2/5 will be:

Please check the attached graph also.

4th option is correct xy=-10

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