determine the force of gravitational attractions between the Earth 5.98 x 10^24 kg and a 70kg boy is standing at sea level, a distance og 6.38 x 10^6m Earth's center ( the universal gravitational constant (G) = 6.6726 x 10 ( raise to power) 11 N/m/kg^ 2)

6.862035456*10^26 m/s^2

Step-by-step explanation:

We know that:

m=70kg

M=Mass of earth=5.98*10^24kg

R=Distance between object's and earth's center=6.38*10^6m

G=6.6726*10^-11 N/m/kg^2

Thus, we can use the equation :

This means the force of gravitational attractions is 6.862035456*10^26 m/s^2

56

step-by-step explanation:

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497