20 POINTS FOR THE FIRST PERSON TO ANSWER Matt has a bag of candy form a party. The bag contains 8 chocolate bars, 5 pieces of gum,
8 lollipops, and 4 jawbreakers. Which statement is true?
A. The probability of randomly selecting a piece of gum is less than the probability of randomly
selecting a lollipop.
B. The probability of randomly selecting a chocolate bar is equal to the probability of randomly
selecting a jawbreaker.
C. The probability of randomly selecting a lollipop is greater than the probability of randomly
selecting a chocolate bar.
D The probability of randomly selecting a piece of qum is

A

Step-by-step explanation:

the probability of selecting a piece of gum is less because there's less gum in the bag then there are lollipops

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.