On a coordinate plane, the center of a circle P is at the point (2, 15) . Point M is located on the circle at (7, 3). Which equation describes circle P?

(x - 2)^2 + (y - 15)^2 = 13^2

Step-by-step explanation:

We know that the general equation for a circle is:

(x - a)^2 + (y - b)^2 = R^2

Where:

(a, b) is the center of the circle

R is the radius of the circle.

First, we know that the center of the circle is the point P, (2, 15)

Now, we also know that point M, (7, 3), is located at the circle.

Then we know that the radius of the circle will be equal to the distance between point P and point M.

Remember that the distance between two points (a, b) and (c, d) is:

Distance = √( (a - c)^2 + (b - d)^2)

Then in our case, we have:

Distance = √( (2 - 7)^2 + (15 - 3)^2) = √(25 + 144) = 13

This means that the radius of the circle is R = 13.

Now we know the radius of the circle and the center of the circle, then we can write the equation of the circle as:

(x - 2)^2 + (y - 15)^2 = 13^2

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.