100 points! I will mark brainliest! Only answers if you know it. Random answers WILL be reported

2sqrt5

Step-by-step explanation:

We know that the shortest distance would be with drawing a perpendicular line through BC and A.

BC is y = -2x+1

Therefore a perpendicular line should have slope 1/2

y = 1/2x + b

-3 = 1/2*-3 + b

b = -3/2

y = -2x+1

y = 1/2x - 3/2

-2x+1 = 1/2x - 3/2

-4x+2 = x - 3

5 = 5x

x = 1

y = 1

now of course the graph shows that already, but we're just proving that again

The x-difference is 4, the y difference is 2, so 16+4 = 18, sqrt20 = 2sqrt5

Solution given:

AB=

units

so shortest distance=AC=4.5units

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3

6 cars because if you have 8 and subtract 2 youll have 6 left over