A piece of wood is 0.9 metres long. It is cut into three unequal pieces.
The first piece is 0.2 metres longer than the second piece.
The third piece is 23 hundredths of a metre shorter than the second piece.
How long is each piece of wood?

The length of the first piece is 0.51 m

The length of the second piece is 0.31 m

The length of the third piece is 0.28 m

Step-by-step explanation:

The question is a simultaneous equation with word problem

The total length of the wood = 0.9 m

The number of pieces the wood is cut into = 3

The length of the first piece = 0.2 m + The length of the second piece

The length of the third piece = The length of the second piece - 0.23 m

Let "y" represent the length of the second piece, let "x" represent the length of the first piece, and let "z" represent the length of the third piece, we have;

x = 0.2 + y...(1)

z = y - 0.23...(2)

x + y + z = 0.9...(3)

Therefore, by substitution, we have;

0.2 + y + y + y - 0.23 = 0.9

3·y - 0.03 = 0.9

3·y = 0.9 + 0.03 = 0.93

y = 0.93/3 = 0.31

y = 0.31

The length of the second piece = y = 0.31 m

From equation (1), we have;

x = 0.2 + y = 0.2 + 0.31 = 0.51

x = 0.51

The length of the first piece = x = 0.51 m

From equation (2), we have;

z = y - 0.23

z = 0.51 - 0.23 = 0.28

z = 0.28

The length of the third piece = z = 0.28 m.

right

step-by-step explanation:

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