A, O and B lie on a straight line segment where A=24,B=40 C=31 State the value of the angles:
i) ii)ZOB=
iii)XOY=
iv)AOY=
v)YOZ=

Step-by-step explanation:

Given angles measure,

m∠a = 24°

m∠b = 40°

m∠c = 31°

ii). Since, all the angles are located at a point O on a straight line AB,

   Therefore, sum of all angles at point O = 180°

   m∠a + m∠b + m∠c + m∠x = 180°

   24° + 40° + 31° + m∠x = 180°

   95° + m∠x = 180°

   m∠x = 180 - 95

   m∠x = 85°

ii). m∠ZOB = c = 31°

iii). m∠XOY = b = 40°

iv). m∠AOY = (a + b)°

                   = (24 + 40)

                   = 64°

v). m∠YOZ = x°

                  = 85°

i dont know men

step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.