Solve the right triangle. Round your answers to the nearest tenth place.

AB = 11.6 inches

AC = 7.3 inches

m∠B = 39°

Step-by-step explanation:

To calculate side AB (c) put b (9 inches) over the sine of β (51°).

c = 9/sin(51)

The sine of an acute angle is defined in the context of a right triangle: for the specified angle, it is the ratio of the length of the side that is opposite that angle, to the length of the longest side of the triangle (the hypotenuse). This would be about 0.777.

c = 9/0.777

I recommend using a fraction here. 0.777 becomes 777/1000. Find the reciprocal (1000/777). Switch the sign to multiplication.

c = 9/1 * 1000/777

Cross cancel if needed.

c = 3/1 * 1000/259

Now multiply.

c = 3000/259

Divide 3000 by 259.

c ≈ 11.5830116 inches ≈ 11.6 inches

Now we know AB. To find AC, find the square root of AB² - BC².

AC = √(11.6² - 9²)

Square both 11.6 and 9.

AC = √(134.56 - 81)

Add 134.56 and 81 to get 53.56

AC = √53.56

Find the square root of 53.56

AC ≈ 7.31846979 ≈ 7.3 inches.

Finding the measure of angle B is comparatively simple. Subtract 51 from 90 to get 39° for angle B.

the answer for this question is : 360°

step-by-step explanation:

we have been given a triangle   we need to tell which one of these is a triangle below to map onto itself.

360° rotation is the complete rotation which eventually leads to the same figure which is given.

the correct will be, that is 360° that will cause the triangle below to map onto itself.

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."