Raj plotted point L in the coordinate plane below. On a coordinate plane, point L is 1.5 units to the left and 4 units up.

He says that the plotted point is (4, negative 1.5). What is Raj’s error?
The x-coordinate should be -4.
The y-coordinate should be 1.5.
The x- and y-coordinates are switched.
Both coordinates should be positive.

The x- and y-coordinates are switched

Step-by-step explanation:

Here, we want to identify the error in the plot

1.5 units to the left, that is negative x-axis (-1.5)

4 units up is 4

So the coordinate point is (-1.5,4)

So the error on what he gave was that both coordinates were switched

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

graph them on a graphing calculator, press 2nd trace. select intersect. hit enter until it says answer. ti 84 works best

step-by-step explanation: