Help with this to pls

A is ur answer

Step-by-step explanation:

a^2 + b^2 = c^2

c = 20

A.) Correct

u = 10√3

v = 10

u^2 + v^2 = c^2

10 = √100

√100 • √3 = √300

√300^2 + 10^2 = c^2

300 + 100 = c^2

400 = c^2

√400 = √c^2

20 = c

B.) Incorrect

u = 20√3

v = 10

u^2 + v^2 = c^2

20 = √400

√3 • √400 = √1200

√1200^2 + 10^2 = c^2

1200 + 100 = c^2

1300 = c^2

√1300 = √c^2

√1300 ≈ 36

C.) Incorrect

u = 20√3

v = 10√2

u^2 + v^2 = c^2

20√3 = √1200

10√2 = √200

u^2 + v^2 = c^2

√1200^2 + √200^2 = c^2

1200 + 200 = c^2

1400 = c^2

√1400 = √c^2

√1400 ≈ 37

D.) Incorrect

u = 10√3

v = 10√2

u^2 + v^2 = c^2

10√3 = √300

10√2 = √200

u^2 + v^2 = c^2

√300^2 + √200^2 = c^2

300 + 200 = c^2

500 = c^2

√500 = √c^2

√500 ≈ 22

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

hm let me think hm think think hm think yes