Write the linear equations in slope-intercept form with a slope of 5 and point (2, -20)

We conclude that the linear equation in slope-intercept form with a slope of 5 and point (2, -20) is:

Step-by-step explanation:

The slope-intercept form of the line equation

where

Given

The slope m = 5

The point (2, -20)

now substitute (x, y) = (2, -20) and m = 5 in the slope-intercept form of the line equation

y = mx+b

-20 = 5(2) + b

10 + b = -20

subtracting 10 from both sides

10 + b - 10 = -20 - 10

b = -30

Thus, the y-intercept b = -30

so substituting b = -30 and m = 5 in the slope-intercept form of the line equation

y = mx+b

y = 5x + (-30)

y = 5x - 30

Therefore, the linear equation in slope-intercept form with a slope of 5 and point (2, -20) is:

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.

the answer is d

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