10 points :) Square OABC is drawn on a centimetre grid.

O is (0,0) Ais (3,0) Bis (3, 3) C is (0, 3)

Write down how many invariant points there are on the perimeter of the square when

OABC is reflected in y = x

No invariant point

Step-by-step explanation:

Yo!

When we translate a form, in this case a polygon We must observe the direction of the vector. Since our vector is:

1) Let's apply  that translation to this polygon, a square. Check it below:

2) The invariant points are the points that didn't change after the transformation, simply put the points that haven't changed.

Examining the graph, we can see that no, there is not an  invariant point, after the translation. There is no common point that belongs to OABC and O'A'B'C' simultaneously. All points moved.

I hope you understood !

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

hope this !

~just a girl in love with shawn mendes

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