The vertices of a triangle are located at L(4, –3), M(1, –3), and N(1, 0). What is the approximate perimeter of triangle LMN?

Step-by-step explanation:

you need to find the distance between points L, M, N to know the length of sides LM, MN, NL

use the distance formula

d= √(x2-x1)² +(y2-y1)², where the points are (x1, y1) and (x2, y2)

LM = √(4-1)² + (-3- -3)² = √3² + 0² = 3

MN = √(1-1)² + (-3-0)² = √0² + 9 = 3

NL = √(4-1)² + (-3-0)² = √3² + 9 = √18 = 3√2

The perimeter is LM+MN+NL = 3+3+3√2 = 6+3√2 ≈ 10.243

-6 is the correct option from the above given options

26

step-by-step explanation: