A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Use equation, find the maximum height reached by the rocket, to the nearest 10th of a foot . Y=-16x^2+261x+130

Maximum height of the rocket = 1194.39 feet.

Step-by-step explanation:

The equation that shows the height of the rocket, y in feet, is related to the time after launch, x in seconds is as follows :

...(1)

We need to find the maximum height reached by rocket. For maximum height,

Put x = 8.15 s in equation (1).

So, the maximum height of the rocket is 1194.39 feet.

the answer is c hope it

step-by-step explanation:

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