How can one sixthx _ 5 = one fifthx + 2 be set up as a system of equations?
6y _ x = _30
5y _ x = 10

5y + x = _30
5y + x = 10

6y _ 6x = _30
5y _ 5x = 10

5y + 5x = _30
5y + 5x = 10

.

Step-by-step explanation:

Given

Let,

By cross multiply we get

By subtraction property of equality

Let ,

By cross multiply we get

By subtraction property of equality we get

Hence, .

6y - x = -30

5y - x = 10

Step-by-step explanation:

one sixth x - 5 = one fifth x  + 2 is equal to (1/6)*x - 5 = (1/5)*x + 2. Isolating x, we get:

(1/6)*x - 5 = (1/5)*x + 2

(1/6)*x - (1/5)*x = 2 + 5

(-1/30)*x = 7

x = -210

Now we want to isolate x from the next system of equations

6y - x = -30  (eq. 1)

5y - x = 10 (eq.  2)

To do so, we follow the next steps. First multiply eq. 2 by 6/5

(6/5)*(5y - x) = (6/5)*10

6y - (6/5)*x = 12 (eq. 3)

Next, subtract eq. 3 to eq. 1

6y - x = -30

-

6y - (6/5)*x = 12

- x + (6/5)*x = -30 - 12

(1/5)*x = -42

x = -42*5 = -210

And this is the value of x we wanted to find.

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.

yes the data was not prsented

step-by-step explanation: