Ajuggler throws a ball in the air, releasing it 5 feet above the ground with an initial
velocity of 15 feet per second. She
catches the ball with her other hand when
the ball returns to 5 feet above the
ground. If the equation, y=-16x2 + 15x,
gives the path of the ball from hand to
hand, find how high she throws the ball
(round to the nearest hundredth).

step 1. The vertex is when x = -b/2a (by definition)

step 2. a = -16, b = 15. x(vertex) = -15/2(-16) = 15/32

step 3. y(vertex) = -16(15/32)^2 + 15(15/32) = 225/64 = 3 33/64

step 4. since the ball started at a height of 5 feet you add 5.

step 5. 3 33/64 + 5 = 8 33/64.

594 square inches

step-by-step explanation:

vote !

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.