Bob is 25 years younger than his father and 27 years older than his son. Together, the sum of their ages is 100. What is each
of their ages?

Bob = 34, father = 59, son = 7

Step-by-step explanation:

Use a system of equations:

Bob = x

Father = x + 25

Son = x - 27

Add them all together, set equal to 100 and solve:

x + x + 25 + x -27 = 100

3x - 2 = 100

3x = 102

x = 34 (bob)

Then plug x back into the equations to solve for father and son age:

34 + 25 = 59 (father)

34 - 27 = 7 (son)

Then you can check your work by adding 34+59+7 and you get 100.

Bob son is 7 years

Father's age is 59 years

Bob is 34 years

Step-by-step explanation:

Bob age be x

Father age be y

Son's age be w

Bob is younger means father is older;

y = 25+x ; x = y -25

x = 27 + w

y-25 = 27+w

y = 27+25+w = 52 +w

x + y + w = 100

27+w + 52+w +w = 100

79+3w = 100

3w = 100-79 = 21

w = 21/3 = 7 years

y = 52+w = 52+7 = 59 years

x = 27 + w = 27 +7 = 34 years

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

60

step-by-step explanation: