4) In A ABC and ADEF, if O(AB) = O(DE), I ZABC = IZDEF and I(BC) =
O(EF) then by
test
they are congruent.
O a) A-S-A
O b) S-A-S
O c) A-A-S
O d) S-S-S

step-by-step explan mxfcg'k; uafwgzfgjhklhgation:

people grow faster than other people.

step-by-step explanation:

should you really be posting this isn't math boi.

the photograph is photographer and- in the process- ourselves.

step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.