Jimmy's school is selling tickets to the annual dance competition. On the first day of ticket sales
the school sold 6 adult tickets and 4 child tickets for a
total of $88. The school took in $186 on
the second day by selling 12 adult tickets and 9 child
tickets. Find the price of an adult ticket and
the price of a child ticket.

A= adult ticket c=child ticket
1. 6a+4c=88
12a+9c=186
2. so you need to multiply the top number by -2 so you can cancel out the 12a
-2(6a+4c=88)=. -12a-8c=-176
3. then you add them all together
12a+9c=186
-12a-8c=-176
——————————-
c=10
4. now you have to find ‘a’
6a+4(10)=88
6a+40=88
-40. -40
6a=48
divide both sides by 6
a=8
And your final answer should be (8,10)
hoped this helped:)

$7.50x+$4.50y=midk it's been awhile since i've done one of these