what is the equation of the line that is perpendicular to the line y=-3x+2 and passes through (3,-1)​

y=x/3−2.

Step-by-step explanation:

find the equation of the line perpendicular to the line y=2−3x passing through the point (3,−1).

The equation of the line in the slope-intercept form is y=2−3x.

The slope of the perpendicular line is negative inverse: m=13.

So, the equation of the perpendicular line is y=x3+a.

To find a, we use the fact that the line should pass through the given point: −1=(13)⋅(3)+a.

Thus, a=−2.

Therefore, the equation of the line is y=x3−2.

y=x/3−2.

step-by-step explanation:

i can't see the picture : /