Stephen rolls a fair dice 78 times. How many times would Stephen expect to roll a number greater than 2?

52 times

Step-by-step explanation:

Given

-- Number of times

Required

Determine the expected times to get > 2.

In a fair dice, the outcome > 2 are:

The probability of the above is:

The number of times is calculated using:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

it's d

step-by-step explanation: