What is the solution to |x − 6| ≥ 5? A. 1 ≤ x ≤ 11 B. -11 ≤ x ≤ 1 C. x ≥ 11 or x ≤ 1 D. x ≥ 1 or x ≤ -11

Deepak plotted these points on the number line. point a: –0.3 point b: – 3 4 point c: – 11 4 point d: –0.7 which point did he plot incorrectly?

Solve the following: 12(x^2–x–1)+13(x^2–x–1)=25(x^2–x–1) 364x–64x=300x

Can someone me with this? i’m not sure what to put for my equations.