I need help very fast please !

Jump discontinuity at x = -2 & infinite discontinuity at x = 0.

Step-by-step explanation:

Hi again,

In this example, we see that there is a jump discontinuity at x = -2 because the line hypothetically "jumps" from y = 2 to y = 0. (just a way to remember these terms)

In addition, there is an infinite discontinuity at x = 0 because the green function will become infinitely close to x = 0 but never crosses nor touches it.

Hope this explanation was helpful. Cheers.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

15% chance.

step-by-step explanation:

3/10 times, the 5 year old will get a tablet. 5/10 times, the 13 yer old will get a tablet. multiply both fractions to get 15/100 times, both would have a tablet.