What is the equation of the line that passes through the point (7, 1) and is parallel to the line with the equation y=4x−1?

Step-by-step explanation:

y=4x-1

y-1=4(x-7)

y-1=4x-28

y=4x-27

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9

that one look

step-by-step explanation: