Add.
(a2+6)+(4a+6)

What is the answer?

Look at the explanation to understand the answer.

Step-by-step explanation:

Step 1.

Rewrite (a2) in a2 + 6 so the a is before 2

(a2 + 6) + (4a + 6) ⇒ (2a + 6) + (4a + 6)

Step 2.

We'll need to organize 2a + 6 + 4a + 6 into groups of like terms, so we can combine them easier.

They're two groups of like terms in the expression.

First group: 2a and 4a

Second group: 6 and 6

Now, rewrite it so the 6 is added by the other 6.

2a + 4a + 6 + 6

Step 3.

We'll need to combine like terms in 2a + 4a + 6 + 6 by adding all the numerical coefficients and copying the literal parts, if any. No numerical coefficient implies value of 1. Numerical 'like' terms will be added.

We already know the groups with like terms.

First group: 2a and 4a

Second group: 6 and 6

Let's solve.

2a + 4a = 6a

6 + 6 = 12

Combine 6a and 12 up and you'll get your answer.

6a + 12 is the answer.

idk

step-by-step explanation: