Find the area of the shaded region. Round your answer to the nearest tenth if needed.

2B

The area of the park is calculated through the equation,

A = 0.5ab(cos C)

Substituting the given above,

A = 0.5(533 ft)(525 ft)(cos 53°)

A = 84201.44 ft²

2. We find the radius of the second figure by the equation,

r = C / 2π

Substituting,

r = (30 in) / (2π) = 4.77 in

The radius of the first one is 9 inches. Getting the difference of these two figures will give us an answer of 4.225 inches.

Thanks Useless

ansverwinterblanco

Diameter of the basketball rim = 18 inches

Circumference of the basketball = 30 inches

You would have to fin the area so= pi*r^2

Basketball rim = 3.14 * (18/2)^2 = 3.14 * 9^2 = 3.14 * 81 = 254.34 in^2

The find the Circumference so= 2*pi*r

30 = 2*3.14*r

r = 30 / (2*3.14) = 30 / 6.28 = 4.78 inches

basketball = 3.14 * (4.78)^2 = 3.14 * 22.85 = 71.75 in^2

254.34 - 71.75 = 182.59 in^

hey seth! : )

i’m not 100% sure, but i think it’s b

hope this ya : p

miss u!

- nicole

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length