The function y = -16t+^2 40 represents the height y (in feet) of a water droplet t seconds after falling from an icicle. After how many seconds does the water droplet hit the ground? Round your answer to two decimal places. ​

The water droplet will hit the ground 1.58 seconds after it started falling.

Step-by-step explanation:

The function:

y = -16*t^2 + 40

represents the height of a water droplet t seconds after falling from an icicle.

We want to find the value of t such that the water droplet hits the ground, and this will happen when y = 0.

Then we only need to solve the equation:

0 = y =  -16*t^2 + 40

0 =  -16*t^2 + 40

16*t^2 = 40

t^2 = 40/16

t = √(40/16) = 1.58

The water droplet will hit the ground 1.58 seconds after it started falling.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

step-by-step explanation: s