When an object is thrown upwards with a speed of 64 ft/sec, its height above the ground is given by the function h(t)=−16t2+64t , where t is the time in seconds after it has been thrown. At what time will the object reach its highest point?

The object will reach its highest point 0.5 seconds after it has been thrown.

Step-by-step explanation:

The object reaches its maximum height when velocity is equal to zero, the velocity is the derivative of function height. That is:

(1)

Where is the velocity of the object at time , in feet per seconds.

If we know that and , then the time when object reaches its highest point is:

The object will reach its highest point 0.5 seconds after it has been thrown.

b

step-by-step explanation:

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn