Agroup of college students built a self-guided rover and tested it on a plane surface. they programmed the vehicle to move along the path
a–b–c–d–a shown on the coordinate plane. what distance will the rover cover if it completes one circuit?

36 meters
40 meters
54 meters
60 meters
68 meters

The answer is 40 meters

Using the formula √(x2-x1)²+(y2-y1)²  on each line to get the distance, then adding them together to get the total perimeter.

line AB=2

(2,11) (4,11)

√(4-2)²+(11-11)²

√4

2

line BC=15

(4,11) (16,2)

√(16-4)²+(2-11)²

√12²+(-9)²

√144+81

√225

15

line CD=14

(16,2) (2,2)

√(2-16)²+(2-2)²

√(-14)²+(0)²

√196

14

line AD=9

(11,2) (2,2)

√(2-11)²+(2-2)²

√-9²+0²

√81

9

Since line AB=2, BC=15, CD=14, and AD=9.

2+15+14+9=40

giving you a final answer of 40 meters

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13