You have a 3-card deck containing a king, a queen, and a jack. you draw a random card, then put it back and draw a second random card. calculate the probability that you draw exactly 1 king.

Probability that you will draw exactly 1 king

P(draw both jacks) = 1/3*1/3 = 1/9P(no jacks) = 2/3*2/3 = 4/9P(1 jack) = 1 - 1/9 - 4/9 = 4/9

Did you get there answer to 44?

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.