Awnser i fraction form 4 3/4 times 3 3/5 times 15

Simplify the following:
(4 + 3/4) (3 + 3/5)×15

Put 3 + 3/5 over the common denominator 5. 3 + 3/5 = (5×3)/5 + 3/5:
(4 + 3/4) (5×3)/5 + 3/5 15

5×3 = 15:
(4 + 3/4) (15/5 + 3/5)×15

15/5 + 3/5 = (15 + 3)/5:
(4 + 3/4) (15 + 3)/5×15

15 + 3 = 18:
(4 + 3/4)×18/5×15

Put 4 + 3/4 over the common denominator 4. 4 + 3/4 = (4×4)/4 + 3/4:
(18×15)/5 (4×4)/4 + 3/4

4×4 = 16:
((16/4 + 3/4)×18×15)/5

16/4 + 3/4 = (16 + 3)/4:
(18×15)/5 (16 + 3)/4

16 + 3 = 19:
19/4×18/5×15

19/4×18/5×15 = (19×18×15)/(4×5):
(19×18×15)/(4×5)

15/5 = (5×3)/5 = 3:
(19×18×3)/4
The gcd of 18 and 4 is 2, so (19×18×3)/4 = (19 (2×9) 3)/(2×2) = 2/2×(19×9×3)/2 = (19×9×3)/2:
(19×9×3)/2

19×9 = 171:

(171×3)/2

171×3 = 513:

513/2

The point (5, 10) will work for the rule y=x+5.y= 10 x= 510=5+510=10therefore the ordered pair (5, 10) works for the rule