Given that x and y are positive integers and (x*2)+x(2^2)+(y*2^3)+(y*2^4)=42, what is the value of xy? PLEASE HELP Note: Answer is not x=0, y=7 or y=0, x=7

x = 3, y = 1

Step-by-step explanation:

If your question is this: 2x + 4x + 8y + 16y = 42

6x + 24y = 42

3x + 12y = 21

For x and y are positive integers, there is only 1 set of x = 3 and y = 1 is the solution  (because x = 7 and y = 0 is excluded)

check: 6 + 12 + 8 + 16 = 42

5 pm

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )