In a certain country the heights of adult men are normally distributed with a mean of 69 inches and a standard deviation of 2.2 inches. The country's military requires that men have heights between 64.6 inches and 73.4 inches.

Complete Question

In a certain country the heights of adult men are normally distributed with a mean of 69 inches and a standard deviation of 2.2 inches. The country's military requires that men have heights between 64.6 inches and 73.4 inches.

What percentage of this country's men are eligible for the military based on height?

95.45 %

Step-by-step explanation:

We solve using z score formula

z-score iis z = (x-μ)/σ, where

x is the raw score

μ is the population mean = 69

σ is the population standard deviation = 2.2

For x= 64.6 inches

z = 64.6 - 69/2.2

z =-2

Probability value from Z-Table:

P(x = 64.6) = 0.02275

For x= 73.4 inches

z = 73.4 - 69/2.2

z = 2

Probability value from Z-Table:

P(x<73.4) = 0.97725

The probability of this country's men are eligible for the military based on height is calculated as:

p(x = 73.4) - p( x = 64.6)

0.97725 - 0.02275

= 0.9545

Converting to Percentage is

= 0.9545 × 100

= 95.45 %

a

explanation:

step-by-step explanation:

if x = 2 you have to find x to finish the problem