One of the races you have entered has a road racing bicycle as a prize. First Prize Bike

Component Weight (kg) Weight (g)
Frame (carbon) 1.07 kg 1070 g
Wheels 1.52 kg 1520 g
Brakes 0.31 kg 310 g
Saddle 0.26 kg 260 g
Pedals 0.18 kg 180 g
Other parts 5.80 kg 5800 g
What is the combined weight of the first prize bike in kg?
kg
The first prize bike’s frame weighs 1070g.

The second prize bike’s frame weighs 75g less.
What is the weight of the second prize bike’s frame in g?

i'm sorry i don't know

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752